A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

Sep 25, 2010 · That second memory address, then, is expected to hold an int. Do note that, while you are declaring a pointer to an int, the actual int is not allocated. So it is valid to say int *i = …

int* i, int * i, int*i, and int *i are all exactly equivalent. This stems from the C compiler (and it's compatible C like systems) ignoring white space in token stream generated during the process …

I saw someone using this in one answer: void methodA(const int*& var); I couldn't understand what the argument means. AFAIK: const int var => const int value which can't …

7 c is a double variable, but the value being assigned to it is an int value because it results from the division of two int s, which gives you "integer division" (dropping the remainder). So what …

Dec 17, 2013 · │int││int││int││int││int││int││ └───┘└───┘└───┘└───┘└───┘└───┘└┄ Of course, there's no reason they can't all …

In C#, int and Int32 appear to be the same thing, but I've read a number of times that int is preferred over Int32 with no reason given. Are the two really the same? Is there a reason …

Dec 29, 2022 · For INT and other numeric types that attribute only specifies the display width. See Numeric Type Attributes in the MySQL documentation: MySQL supports an extension for …

Jan 28, 2012 · The real reason that this can happen is that C is a weakly typed language. But unsigned int and int are really different.

Mar 14, 2012 · int is a primitive type allowed by the C# compiler, whereas Int32 is the Framework Class Library type (available across languages that abide by CLS). In fact, int translates to …